The particulate phosphorus released can be expressed by the exchange-adsorption kinetic equation t/x_P(t) = t/x_P(eq) + B'. The values of x_P(eq) and Δx_P(eq) calculated from the equation are very close to those measured. The maximum of phosphorus released under specified conditions can also be estimated.

The increase rate of dissolved phosphorus is governed by the first-order kinetic model: lnC = k_1pt + B. A linear relationship exists between rate constant (k_1p) and the initial adsorption rate (a₀); k_1p = 0.32a₀ + 0.016. The net increase rate is k_0(1P) ~ 0.02/d. It has been estimated that if 10² tons of wastewater are discharged a day, the environmental phosphorus capacity of the sea area will reduce by 5 kg every day because of the release of particulate phosphorus into the water body.